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Topic: on real part of [(1+isqrt(7))/2]^n
Replies: 20   Last Post: Feb 15, 2014 5:52 AM

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Robin Chapman

Posts: 412
Registered: 5/29/08
Re: on real part of [(1+isqrt(7))/2]^n
Posted: Feb 11, 2014 11:23 AM
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On 11/02/2014 16:12, konyberg wrote:

> a_n = Re(a^n)
> a^n = (x + iy)^n = r^n (cos(nu) + isin(nu))
> a_n = r^n cos(nu)
> a = (1 + isqrt(7))/2 gives r = sqrt(2), and u = pi/4 (45 deg)

Oh no, u = tan^{-1}(sqrt(7)) which is not a rational multiple of pi.

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