
Re: Help Needed in math
Posted:
Apr 29, 2014 11:02 PM


On Tue, 29 Apr 2014, konyberg wrote: > > Find the largest values of the integer a for which ax^25x3 is negative for all values of x. > set a = (5x + 3) / x^2 and find the minima of this function. This will, with > your constraints, give the answer: a = 3 5/x + 3/x^2 5/x^2  6/x^3 = 0 5x + 6 = 0 x = 6/5 a = (6 + 3)/(36/25) = 25/12 Why does the minimum work?

