quasi
Posts:
12,012
Registered:
7/15/05


Re: Help Needed in math
Posted:
May 1, 2014 10:23 PM


William Elliot wrote: >konyberg wrote: >>William Elliot wrote: >>>konyberg wrote: >>>> >>>>f(x) = (5x + 3) / x^2, x <> 0 >>> >>>What's f?
Are you blind?
>>I don't understand the question.
>Did you define f as f(x) = (5x  3)/x^2?
No, he wrote
f(x) = (5x + 3)/x^2
>>>>If a < f(x) for all x, then a has to be less than the >>>>global minimum of f(x). >>>> >>>>The global minimum of f(x) = 25/12. >>>> >>>>The largest integer less than this is 3. > >f'(x) = 5/x^2  (5x + 3)/2x^3 = 0;
No.
>The extremum point, x = 3/5 when f(x) = 0,
Presumably you meant when f'(x) = 0, not when f(x) = 0.
>inflection point.
Not when you use the correct f'(x).
>What you're doing is unfathomable.
Unfathomable to you perhaps.
Nevertheless, konyberg's argument is correct.
quasi

