Compute the integral from 0 to 1 of ln(1+x)/(1+x^2)dx. Hint: Use the substitution y+1=2/(x+1)
I'm pretty sure I need to get this in the form of the integral of ln u du. So I use the substitution given and let u = 2/(x+1) but when I compute the derivative of this I get [(x+1)*0 - 2(1)]/(1+x)^2 = -2 /(1+x)^2 which does not equal 1/(1+x^2) like I need. I didnt get too far trying integration by parts but maybe that is the way to go? I doubt it because of the hint so pretty sure I am just missing something getting it in the form of ln u du.
Any help is appreciated! Thanks! This is just a practice problem for a final and not something I have to turn in.