
Re: 1.39  What exactly is the Mean value Theorem?
Posted:
Jun 19, 2014 7:31 AM


WizardOfOz <Wizard@Oz.com> wrote: > John Gabriel <thenewcalculus@gmail.com> wrote in > news:929be574b8814442ad67e741fb1823de@googlegroups.com:
[snip]
>> If f is a differentiable function over (a,b), then {f(b)f(a)}/(ba) >> is the (natural) average of all the ordinates of f' over (a,b). > > OMG ... no. Really? That is simply hilarious. You're a total > fucking moron.
It is true. Try it out with a simple example such as f(x) = x^2 a = 4 b = 7
Dirk Vdm

