"Nasser M. Abbasi" schrieb: > > On 6/26/2014 4:47 AM, email@example.com wrote: > > > Actually, I didn't mean to split the integrand into sooooo many parts; > > Ok, But more parts, means each part is smaller in leaf count. Hence > it should be easier for a CAS to solve, I would have thought. So > in this case, the more parts, the better. One pay extra waiting > time for easier to solve pieces. At least that is what I expected to > happen ;) > > > what I had in mind was to separate the 9+9 logarithms into 9 terms of > > 1+1 logarithm (pairing with the corresponding logarithm from the other > > group serves to keep the integral real), with a tenth term formed by the > > non-logarithmic remainder. Thus, my second integral covers the (easy to > > integrate) full remainder, and my third integral the first (relatively > > hard to integrate) logarithm from each group of nine. > > > > Will try again and see what I can do. >
It does not matter for the non-logarithmic part of the integrand, but with the logarithmic terms there is the danger that the integrals are no longer elementary if the algebraic prefactor is taken apart. I just do not know as I did not investigate this point.