```Date: Oct 4, 2017 2:49 AM
Author: plutonium.archimedes@gmail.com
Subject: 2017 Nobel prize in Math        o-:^>___?   goes<br>	 to Franz of Germany;; For- reverse-math

John Gabriel:: here is an exciting day in Germany where Franz has just won the Nobel Prize in Math, and here is Alouatta, here to explain what Franz has achieved with Reverse-Math.Alouatta:: yes, John, Reverse Math is where you compose a proof in which everything, every statement is wrong, except for one sentence in the proof that is possibly true, all the rest of the sentences are crap.John;; is there a need for such a mathematics? I mean, isn't it difficult enough to get someone to have a full page without errors?Alouatta:: that is the boldness of Reverse Math, which is extremely difficult to do, to compose all lies, except for one sentence. Most math professors can only get 5 true sentences, whereas Franz has now eclipsed all fake sentences except one. See in Franz's classical report below.On Tuesday, October 3, 2017 at 11:14:58 AM UTC-5, Me (Franz of Germany) wrote: > > You obviously don't know the general equation for an ellipse. > > Hint: > > (1/ab)y^2 + (4/h^2)(x - h/2)^2 = 1 > > is the equation for an ellipse. > > If a = b = r and h = 2r we get the equation of a circle: > > (1/r^2)y^2 + (1/r^2)(x - r)^2 = 1 > > => (x - r)^2 + y^r = r^2 > > Are you really too dumb to understand these simple things, Archie? > > Here's the complete proof again:> > > > Cone/Cylinder (side view): > > > > > >                 / | \   (with b <= a) > > >                /b |  \ > > >               /---+---´ <= x = h > > >              /    |´   \ > > >             /   ´ |     \ > > >            / ´    |      \ > > >  x = 0 => ´-------+-------\ > > >          /    a   |        \ > > > > > > (cone: b < a, cylinder: b = a = r) > > > > > > r(x) = a - ((a-b)/h)x > > > d(x) = a - ((a+b)/h)x > > > > > > y(x)^2 = r(x)^2 - d(x)^2 = ab - ab(2x/h - 1)^2 = ab(1 - 4(x - h/2)^2/h^2 > > > > > > => (1/ab)y(x)^2 + (4/h^2)(x - h/2)^2 = 1  ...equation of an ellipse > > qed. > > Now lets just look at some "properties" of this ellipse: > > > > Some considerations: > > > > > > => y(h/2 + x')^2 = ab - ab(2(h/2 + x')/h - 1)^2 = ab - ab(2x'/h)^2 > > > > > > => y(h/2 + x') = sqrt(ab) * (sqrt(1 - (2x'/h)^2) ...symmetric relative to h/2 (hence Ec = cF) > > > > > > => y(h/2) = sqrt(ab) (= Gc = cH)
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