```Date: Oct 6, 2017 2:25 PM
Author: bursejan@gmail.com
Subject: Re: Can two series, both diverges, multiplied give a series that converges?

Sorry, for the foundation, we need:   /* the first series */   function rational s(n natural) {      /* something */   }   /* the second series */   function rational t(n natural) {      /* something */   }   /* the product series */   function rational r(n natural) {      return s(n)*t(n);   } Am Freitag, 6. Oktober 2017 20:24:39 UTC+2 schrieb burs...@gmail.com:> Corr.:> >    /* the first series */>    function real s(n natural) {>       /* something */>    }> >    /* the second series */>    function real t(n natural) {>       /* something */>    }> >    /* the product series */>    function real r(n natural) {>       return s(n)*t(n);>    }> > Am Freitag, 6. Oktober 2017 20:12:42 UTC+2 schrieb burs...@gmail.com:> > is quite simple to understand:> > > >    /* the first series */> >    function real s(n real) {> >       /* something */> >    }> > > >    /* the second series */> >    function real t(n real) {> >       /* something */> >    }> > > >    /* the product series */> >    function real r(n real) {> >       return s(n)*t(n);> >    }
```