Date: Mar 15, 2006 8:56 AM
Author: Dik T. Winter
Subject: Re: Reason for operator precedence
In article <dv6nv8$chc$1@agate.berkeley.edu> magidin@math.berkeley.edu (Arturo Magidin) writes:

...

[ Without operator precedence ]

...

> If you want to put in the square, you

> would need to do something like

>

> bx + c + (a(x^2)).

>

> Higher degree polynomials would be even harder.

It can be done:

a * x + b * x + c

(thanks to Horner), but it is not immediately clear that it is a

polynomial.

--

dik t. winter, cwi, kruislaan 413, 1098 sj amsterdam, nederland, +31205924131

home: bovenover 215, 1025 jn amsterdam, nederland; http://www.cwi.nl/~dik/