Date: Jul 13, 2006 11:32 AM
Author: Toni Lassila
Subject: Re: A=B*C how to get B?
On 13 Jul 2006 08:15:09 -0700, email@example.com wrote:
>I have a system of equations that can be written in matrix vector
>notation as follows:
>In a book i saw that B = A* C' * (C*C')^(-1)
C'(CC')^(-1) is called the pseudoinverse of C.
>However, i do not recall how to get to that solution. can anybody help
>me with this?
AC' = BCC' => B = AC'(CC')^-1 provided that the inverse exists. It
does when C has rank n.