Date: Mar 11, 2008 1:24 PM
Author: Tony Orlow
Subject: Re: An Argument for the Subroot Node

G. Frege wrote:
> On Tue, 11 Mar 2008 16:51:03 +0100, G. Frege <nomail@invalid> wrote:
>
> Oopos... typo/thinko...
>

>>> According to it, the perimeter of a triangle is a tree...
>>> which, of course, it is not.
>>>

>> Wait a second. If the nodes of your triangle were, say a, b, c then
>> (say) a, b would be connected by more than one path:
>>
>> p_1 = ((a,b))
>>
>> p_2 = ((a,b), (b,c), (c,a), (a,b))
>>

> No?
>
>
> F.
>


a and b are connected by ((a,b)) and ((a,c),(c,b)), two simple paths,
and thus there exists a cycle.

T.