Date: Nov 11, 2008 4:59 AM
Author: William Elliot
Subject: Re: Exponentation of Complex Numbers

On Mon, 10 Nov 2008, G. A. Edgar wrote:

> >     0^x = 0
> >
> > provided x /= 0.

... provided 0 < x.

> So you want 0^(-1) = 0 ?

On the other hand, oh the heck with it.
For real numbers, exponentation a^x is defined only for 0 < a.

Thus no nonsense like
	-1 = (-1)^1 = (-1)^(2/2) = ((-1)^2)^(1/2) = 1^(1/2) = 1

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