Date: Oct 16, 2009 3:37 PM
Author: gaya.patel@gmail.com
Subject: Re: n square free) ^ ( d I n and u = v (mod d) --> f(u) = f(v) (mod <br> d) ) --> (f is a polynomial over Z_n)
On Oct 16, 10:10 am, Olivier <O...@nowhere.wd> wrote:

> G Patel a écrit :

>

> > How can I show that for any squarefree n and function f from Z_n to

> > Z_n that has the propery that- whenever d I n and u = v (mod d) then f

> > (u) = f(v) (mod d) - must be a polynomial over Z_n ?

>

> This is true when n is a prime.

> Use the chinese remainder Theorem.

> A.O.

is there a counterexample for when n is squarefree and not a prime?

how about when n is not squarefree?