Date: Oct 16, 2009 3:37 PM
Subject: Re: n square free) ^ ( d I n and u = v (mod d) --> f(u) = f(v) (mod <br> d) ) --> (f is a polynomial over Z_n)
On Oct 16, 10:10 am, Olivier <O...@nowhere.wd> wrote:
> G Patel a écrit :
> > How can I show that for any squarefree n and function f from Z_n to
> > Z_n that has the propery that- whenever d I n and u = v (mod d) then f
> > (u) = f(v) (mod d) - must be a polynomial over Z_n ?
> This is true when n is a prime.
> Use the chinese remainder Theorem.
is there a counterexample for when n is squarefree and not a prime?
how about when n is not squarefree?