Date: Nov 4, 2009 10:48 PM
Author: gaya.patel@gmail.com
Subject: Re: eigenvalues of A

On Nov 4, 9:56 pm, G Patel <gaya.pa...@gmail.com> wrote:
> true or false.... eigenvalues of A are same as eigenvalues of kA
> (because if v is eigenvector for A, then kv is eigenvector for kA)

if c is eigenvalue of A, then Ax = cx for nonzero x, multiply both
sides by nonzero scalar k: (kA)x = c(kx) , thus c is also eigenvalue
of kA?