Date: Nov 4, 2009 10:48 PM Author: gaya.patel@gmail.com Subject: Re: eigenvalues of A On Nov 4, 9:56 pm, G Patel <gaya.pa...@gmail.com> wrote:

> true or false.... eigenvalues of A are same as eigenvalues of kA

> (because if v is eigenvector for A, then kv is eigenvector for kA)

if c is eigenvalue of A, then Ax = cx for nonzero x, multiply both

sides by nonzero scalar k: (kA)x = c(kx) , thus c is also eigenvalue

of kA?