```Date: May 21, 2011 5:54 AM
Author: Ramiro Barrantes-Reynolds
Subject: Re: Maximize a single variable and solve for the rest

thank you Daniel and Bob, this solved it, please excuse my confusion.On 5/20/11 6:49 AM, Bob Hanlon wrote:> It makes no sense to Maximixe the LHS of an equation since it is fixed to be equal to the RHS. Presumably you are trying to maximize the variable c.>> r1 = 3/4;> r2 = 1;>> Maximize[{c, b == c*r1, h + s + b + d == 1, d == c*r2, h == s,>    b + d<= 9/10}, {h, s, b, d, c}]>> {18/35, {h ->  1/20, s ->  1/20, b ->  27/70, d ->  18/35, c ->  18/35}}>> Solve[{b == c*r1, h + s + b + d == 1, d == c*r2, h == s, b + d<= 9/10}, {h,>     s, b, d, c}, Reals] // Quiet>> {{h ->  ConditionalExpression[1 - (7*c)/4 + (1/2)*(-1 + (7*c)/4),>      c<= 18/35],>       s ->  ConditionalExpression[(1/2)*(1 - (7*c)/4), c<= 18/35],>       b ->  ConditionalExpression[(3*c)/4, c<= 18/35],>       d ->  ConditionalExpression[c, c<= 18/35]}}>> Since you want c maximized,>> %[[1]] /. c ->  18/35>> {h ->  1/20, s ->  1/20, b ->  27/70, d ->  18/35}>>> Bob Hanlon>> ---- Ramiro<ramiro.barrantes@gmail.com>  wrote:>> =============> Hello,>> I have a problem where I would like to solve an equation (namely (h+s+b> +d==1) with some constraints, while maximizing for a related variable> "c" (c<=9).  Please see below,  any suggestions?>> r1 = 3/4;> r2 = 1;> Block[{h, s, b, d, c},>   NMaximize[{h + s + b + d,>     b == c*r1&&  h + s + b + d == 1&&  d == c*r2&&  h == s&&>      b + d<= 0.9}, {h, s, b, d, c}]]>>   {1., {h ->  0.5, s ->  0.5, (3 c)/4 ->  0., c ->  0., c ->  0.}}>> Should I be using NSolve?>> Thanks in advance,> Ramiro
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