Date: Jul 26, 2012 6:27 PM
Author: Richard Tobin
Subject: Re: What's the geometry meaning of i^i ?

In article <junsli$7n8$>,
Hongyi Zhao <> wrote:

>What's the geometry meaning of i^i ? Here, i is the imaginary unit.

We can naturally define b^x as e^(x log b). The principal value of
log i is pi/2 i, so i^i is e^(-pi/2).

All you need now is a geometric interpretation of log i. For an
imaginary number the log is i times the phase, but I'm not sure
that is really an interpretation.

-- Richard