```Date: Sep 29, 2012 12:19 PM
Author: haroldj.l.jones@gmail.com
Subject: Re: SONNTAG! Symmetries of Nature 'n' Truth about Gravity(& Planck Units).

Of course, there is no Rydberg Gm product or a Rydberg mass in the sense of the operating mechanics.  The Rydberg mass exists as a numerical value because it is there at the heart of the numerical structure of the atom.  The Rydberg mass divided by the planck mass is equal to the Rydberg frequency, 2(3.2898426x10^15).The idea of the Rydberg mass, 1.7951598x10^8, being a mass at all involves the principle frequency that is the Rydberg frequency. The Rydberg frequency is a Compton frequency involving a beam of wave crests where the energy equals the Rydberg energy after a duration of one second.  What I have done is measure it as if it were a Planck frequency.  A Planck frequency amounts to the number of Planck lengths in a Schwarzschild diameter of a given mass.  In this case the Rydberg mass.  The formula for the Rydberg mass can be found in the following way. (c/2)^2 divided by [(137.035989)^2]x1836.1526] and that lot divided by 3.62994678, the quantum adjustor.  From the the Rydberg mass we can work out the Rydberg adjustor, 1.1976017, simply by dividing the Rydberg mass by c/2. If we consider that one good reason why we cannot find a consistent value for G and that is that there exists in numerical structure a whole host of numerical values that have h & c in identical nominal value to our own SI system.  But these 'other' structures also have the Rydberg mass nominally the same to ours.If we take a time-scale mass equal to (c^2)/h, that is 1.356391399x10^50 mass units, those particular mass units cannot be kilograms if their c & h constants are nominally the same as ours. In fact a structure equal to (c^2)/h will have mass units equal to the Planck mass. That means that its Schwarzschild Diameter and therefore its time unit will be one light second divided by the Planck mass.But, the Rydberg mass is constant within this gradient of mass values in the same way as h & c are, therefore, if the Rydberg frequency is equal to the Rydberg mass divided by the Planck mass, then the Rydberg frequency of this particular time unit must be higher than ours by the Rydberg frequency divided by the Rydberg mass which is 3.665236x10^7 multiplied by our Rydberg frequency.The reciprocol of this value must be close to the Planck mass.
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