Date: Nov 27, 2012 11:32 PM
Author: Ray Koopman
Subject: Re: Here's how I did logs ...
On Nov 27, 4:06 pm, djh <halitsk...@att.net> wrote:

> You wrote:

>

> ***

> In your previous post, you said

> "[the] underlying regression is c on (u',u'^2), where u' = u/(1+u)."

>

> Now are you saying that the underlying regression was not that,

> but was ln(c) on (u',u'^2), where u' = ln(u/(1+u^2)) ?

> ****

>

> Sorry for the earlier reference without logs - at the time I typed it

> I was assuming logs to be understood.

>

> So the way I did logs was as follows;

>

> c on (u',u'^2)

>

> where u' = log( $u / ( 1 + $u ) )

> u'^2 = ( log( $u / ( 1 + $u ) ) )^2

>

> (I was going "by analogy", i.e. to square u', whatever it is. )

>

> So, please confirm if:

>

> 1) you want logs or not

> 2) if so, is the above correct? (If not, then what?)

No logs, please. Make it c on (u',u'^2)

where u' = $u / ( 1 + $u )

u'^2 = ( $u / ( 1 + $u ) )^2 .