Date: Dec 7, 2012 12:02 AM
Author: ross.finlayson@gmail.com
Subject: Re: Cantor's first proof in DETAILS
On Dec 5, 9:05 pm, Virgil <vir...@ligriv.com> wrote:

> In article

> <5312c40d-7490-4838-b49c-573a9f2e1...@i2g2000pbi.googlegroups.com>,

> "Ross A. Finlayson" <ross.finlay...@gmail.com> wrote:

>

> > On Dec 4, 1:15 pm, Virgil <vir...@ligriv.com> wrote:

> > > In article

> > > <42cabcca-089d-456f-837a-c1d789bda...@jj5g2000pbc.googlegroups.com>,

> > > "Ross A. Finlayson" <ross.finlay...@gmail.com> wrote:

>

> > > > And Heaviside's step is continuous,

> > > > now. For that matter it's a real function.

>

> > > I already said that the step function is a real function, I only

> > > objected to your claim that it was a continuous function.

> > > --

>

> > Heh, then you said it wasn't, quite vociferously

>

> I objected to it being called continuous. possibly vociferously, but

> your claim that it was continuous deserved vociferous objection.

>

> : you were wrong

> Don't you wish!

>

> , and

>

> > within the course of a few posts wrote totally opposite things. Your

> > memory fails and that's generous, not to mention you appear unable to

> > read three posts back.

>

> > And everybody sees that.

>

> > Then as noted Heaviside's step, a real function, can be simply drawn

> > classically: without lifting the pencil.

>

> Not outside of Rossiana.

>

> http://en.wikipedia.org/wiki/Heaviside_step_function

> The Heaviside step function, or the unit step function, usually denoted

> by H (but sometimes u or ?), is a discontinuous function whose value is

> zero for negative argument and one for positive argument. It seldom

> matters what value is used for H(0), since H is mostly used as a

> distribution.

>

> It's continuous that way.

>

> Not according to Wiki, whom EVERONE here, except possibly WM, trusts far

> more than they trust Ross.

>

> See that phase "discontinuous function"?

>

> Or maybe your as blind as you are thick.

> --

http://en.wikipedia.org/wiki/Heaviside_step_function

* ''H''(0) can take the values zero through one as a removal of the

point discontinuity, preserving and connecting the neighborhoods of

the limits from the right and left, and preserving rotational symmetry

about (0,½).

http://en.wikipedia.org/wiki/Oliver_Heaviside

Looks good to me.

Not so, Hancher: not so.

Regards,

Ross Finlayson