Date: Dec 30, 2012 8:13 AM Author: ungeheuer Subject: L'Hospitals rule Please, if we have:

lim(x to 1)(x/(x-1)-1/lnx))

we get

lim(x to 1) ((xlnx-x+1)/(xlnx-lnx))

now we take that x=1 and we apply LH rule:

how do we get now

lim(x to 1) ((lnx+1-1)/(lnx +1-1/x))

after LH it should be f'(x)/g'(x)

so how did we get the reciprocical value?

Many thanks