Date: Dec 30, 2012 8:13 AM Author: ungeheuer Subject: L'Hospitals rule Please, if we have:
lim(x to 1)(x/(x-1)-1/lnx))
lim(x to 1) ((xlnx-x+1)/(xlnx-lnx))
now we take that x=1 and we apply LH rule:
how do we get now
lim(x to 1) ((lnx+1-1)/(lnx +1-1/x))
after LH it should be f'(x)/g'(x)
so how did we get the reciprocical value?