Date: Dec 30, 2012 8:13 AM
Author: ungeheuer
Subject: L'Hospitals rule

Please, if we have:



lim(x to 1)(x/(x-1)-1/lnx))
we get
lim(x to 1) ((xlnx-x+1)/(xlnx-lnx))
now we take that x=1 and we apply LH rule:

how do we get now
lim(x to 1) ((lnx+1-1)/(lnx +1-1/x))
after LH it should be f'(x)/g'(x)


so how did we get the reciprocical value?
Many thanks