Date: Dec 30, 2012 8:05 PM
Author: Graham Cooper
Subject: Re: This Is a Failed *PROOF* that AD never produces a New Digit Sequence!
On Dec 31, 8:31 am, George Greene <gree...@email.unc.edu> wrote:

> On Dec 29, 10:29 pm, Graham Cooper <grahamcoop...@gmail.com> wrote:

>

> > If you disagree with a numbered point then which one?

>

> Everybody disagrees WITH POINT 4, DUMBASS. IT DOESN'T FOLLOW

> from anything. YOU CAN'T PROVE IT. We by contrast HAVE EASILY

> proved that since for EVERY n, the nth position of the diagonal

> DIFFERS from the nth R on the list AT Rn's nth position,

> THE ANTI-DIAGONAL *IS*NOT*ON* the list. If it WERE on, it would

> have to be on it *AT* some row n. But the anti-diagonal IS NOT

> on the list at row n because Rn DIFFERS from the anti-diagonal IN

> POSITION n.

>

>

>

>

>

>

>

>

>

> > AD METHOD (binary version)

> > Choose the number 0.a_1a_2a_3...., where a_i = 1 if the i-th

> > number in your list had zero in its i-position, a_i = 0 otherwise.

>

> > LIST

> > R1= < <314><15><926><535><8979><323> ... >

> > R2= < <27><18281828><459045><235360> ... >

> > R3= < <333><333><333><333><333><333> ... >

> > R4= < <888888888888888888888><8><88> ... >

> > R5= < <0123456789><0123456789><01234 ... >

> > R6= < <1><414><21356><2373095><0488> ... >

> > ....

>

> > By breaking each infinite expansion into arbitrary finite length

> > segments

>

> > [3] The anti-Diagonal never produces a unique segment

> > (all finite segments are computable)

>

> > [4] The anti-Diagonal never produces a unique sequence

> > of segments (all segment sequences are computable)

>

> MOST of the *infinitely*-long segment sequences ARE NOT computable.

> The fact that all the FINITE ones are DOES NOT IMPLY that the infinite

> ones are also.

> The mystery is why you would think it would.

>

Point 4 inductively follows from point 3.

< <sub-segment> <sub-segment> <sub-segment> >

this sequence of segments.

You opposing argument is that some sequence of sentences cannot be

written down and placed on a stack.

INFINITE STACK OF INFINITE ESSAYS OF FINITE VOCABULARY

in order to be equivalent to a BASE-|VOCAB| List of infinite

strings.

SEGMENT <=> SENTENCE

Herc