```Date: Dec 31, 2012 1:42 AM
Author: John Jens
Subject: Re: From Fermat little theorem to Fermat Last Theorem

On Sunday, December 30, 2012 9:51:08 PM UTC+2, quasi wrote:> John Jens wrote:> > > > >I pick a < p ,proved that do not exist a , b , c > > >rational numbers with 0<a=<b<c and a<p to satisfy > > >a^p+b^p=c^p > > > > No, you never proved the above claim.> > > > You only thought you did.> > > > First you tried to show that the equation> > > >    a^p + b^p = c^p> > > > has no solutions in integers a,b,c,p subject to the> > conditions 0 < a <= b < c, p > 2, a < p.> > > > For the sake of argument, let's allow that claim.> > > > Then you attempted to extend to positive rationals a,b,c. To do > > that, you scale a,b,c down, dividing each by a positive integer > > large enough so the new value of a is less than p. Then you > > claim a contradiction since you already showed that a < p is> > impossible. But you showed that for positive integer values of > > a, not for positive rational values of a, so (barring circular> > reasoning) you don't have your claimed contradiction.> > > > quasiI intentionally choose a < p ,there's no crime to choosean a natural, a < p.If for a < p ,a,b,c, naturals , we can multiply the inequality a^p + b^p != c^p with any rational number,it will remain a inequality.
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