```Date: Jan 6, 2013 12:36 AM
Author: Koobee Wublee
Subject: Re: The Math is still Not Ready

On Jan 5, 8:54 am, Tom Roberts wrote:> Here is General Relativity:>>         On a 4-d Lorentzian manifold M,>         G = T>> where G is the Einstein curvature tensor and T is the energy-momentum tensor.Please allow Koobee Wublee reminds Tom where that overly simplifiedequation[s] above come from.  Let?s follow Hilbert?s footsteps andpull out the following so-called Lagrangian out of Hilbert?s ass.**  L = (R / K + rho) sqrt(-det[g])Where**  L = Lagrangian**  R = Ricci scalar**  K = Constant**  rho = Mass density**  [g] = The metric (a 4x4 matrix)**  det[] = Determinant of a matrixFor the language of convention in this case, [A] means a matrix withelements [A]_ijk... or [A]^ijk...The field equations can be derived in just one step by taking thepartial derivative of the Lagrangian above with respect to [g^-1]^ijwhere [g^-1], a matrix, is the inverse of [g], another matrix, andafter setting each of the partial derivative to null, the result isthe following relationships of matrices.**  [R] ? R [g] / 2 = K rho [g] / 2Where**  [R] = Ricci tensor (another 4x4 matrix)You would call the following.**  [G] = [R] ? R [g] / 2**  [T] = K rho [g] / 2Thus,**  [G] = [T]Koobee Wublee would also like to remind Tom that the above equationhas never been tested with any experimentations, and the best Tom canhope for is the following where the energy momentum tensor is null.**  [G] = 0Where**  [T] = 0Using only diagonal [g], the equation above simplifies into thefollowing where the effect of the ever so celebrated trace term isnullified.  The null Ricci tensor was basically Nordstrom?s work whereSchwarzschild had been working on the solution for years.  That is whywithin a couple months after Hilbert presented the field equations,Schwarzschild published a solution.**  [R] = 0, first proposed by Nordstrom as the field equationsWhere**  R [g] / 2 = The trace term<shrug>> To get SR from GR:>>         Riemann = 0>         Top(M) ~ R^4>> where Riemann is the Riemann curvature tensor on M, and Top(M) is the topology of M.Nonsense, Tom.  If the Riemann tensor is null, the Ricci tensor mustbe null as well in which you end up with the null Ricci tensor abovewhere you can solve for the Schwarzschild metric and other equallyvalid solutions that are able to degenerate into Newtonian law ofgravity at weak curvature in spacetime.  <shrug>The best way to get SR from GR is to set the gravitating mass, M, to0, duh!  <shrug>**  ds^2 = c^2 (1 ? 2 U) dt^2 ? dr^2 / (1 ? 2 U) ? r^2 dO^2Where**  U = G M / c^2 / r>         [Note that approximations are important in applying the theory,>          as this is PHYSICS, not math. Based on your writings around>          here, and your aversion to any intellectual effort, I estimate>          you will never understand this.]Tom, in GR, physics = math, and math = physics.  So, startunderstanding the mathematics involved instead of wishing for what youbelieve in.  <shrug>Faith should not come into any equations of science, no?  <shrug>
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