Date: Jan 12, 2013 5:21 PM
Author: Virgil
Subject: Re: Matheology � 191

In article 
<c971e75b-20e3-4761-b39a-aab5a20a6d9a@d10g2000yqe.googlegroups.com>,
WM <mueckenh@rz.fh-augsburg.de> wrote:

> On 12 Jan., 12:45, Zuhair <zaljo...@gmail.com> wrote:
> > On Jan 12, 11:56 am, WM <mueck...@rz.fh-augsburg.de> wrote:
> >

> > > Matheology § 191
> >
> > > The complete infinite Binary Tree can be constructed by first
> > > constructing all aleph_0 finite paths and then appending to each path
> > > all aleph_0 finiteley definable tails from 000... to 111...

> >
> > No it cannot be constructed in that manner, simply because it would no
> > longer be a BINARY tree.

>
> No? What node or path would be there that is not a node or path of the
> Binary Tree? This is again an assertion of yours that has no
> justification, like many you have postes most recently, unfortunately.


Your claim that there are only aleph_0 possible tails is falsified by
the Cantor diagonal argument:

Any listing of those tails as binary sequences allows the anti-diagonal
constriction of a tail not listed. and if you cannot list them, you have
no proof that they are only countable in number.
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