```Date: Jan 15, 2013 4:12 PM
Author: Virgil
Subject: Re: WMatheology � 191

In article <3e51ac5e-0aa6-4c17-8353-d6db63f3a805@ho8g2000vbb.googlegroups.com>, WM <mueckenh@rz.fh-augsburg.de> wrote:> On 15 Jan., 19:45, Virgil <vir...@ligriv.com> wrote:> > > > That does not help. It can only differ at finite places.> >> > It takes infinitely many finite "places" to make an infinite sequence.> > That does not help you. There are infinitely many finite initial> sequences such that no finite combination of nodes or digits is> missing.But every infinite combination is missing so any infinite combination differs from every finite combination.> > > And it is quite legitimate to speak of some property as belonging to> > "ALL" of those "places" outside of WMytheology, even though the set of> > such "places" must be an infinite set.> > The the following sequence must have all natural numbers as negative> exponents:> > 1) 10^-1> 2) 10^-1 + 10^-2> 3) 10^-1 + 10^-2 + 10^-3> ...> oo) 10^-1 + 10^-2 + 10^-3 + ... (not containig 10^-oo)> > And they all must be in one line. But that line does not exist. There> exists only the limit 1/9. But 1/9 is not a term of this sequence. It> differs from the sequence by having all natural numbers as negative> exponents.You prove my point that the infinite sequence is different from every finite sequence.> > Alas, how can there be all finite terms of the sequence, enumerated by> all finite natural numbers, whereas all natural numbers as exponents> already are beyond the finite terms?Which terms in your        "oo) 10^-1 + 10^-2 + 10^-3 + ... (not containig 10^-oo)"are "beyond all finite terms"?I do not find anything in it that is beyond all finite terms. But then I am not constrained by WMytheology--
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