```Date: Feb 3, 2013 3:26 AM
Author: William Hughes
Subject: Re: Matheology § 203

On Feb 3, 8:51 am, WM <mueck...@rz.fh-augsburg.de> wrote:> On 3 Feb., 00:22, William Hughes <wpihug...@gmail.com> wrote:>>>>>>>>>> > On Feb 2, 11:58 pm, William Hughes <wpihug...@gmail.com> wrote:>> > > On Feb 2, 11:42 pm, WM <mueck...@rz.fh-augsburg.de> wrote:>> > > > On 2 Feb., 23:36, William Hughes <wpihug...@gmail.com> wrote:>> > > > > On Feb 2, 11:15 pm, WM <mueck...@rz.fh-augsburg.de> wrote:>> > > > > > On 2 Feb., 20:11, William Hughes <wpihug...@gmail.com> wrote:>> > > > > > > > > > > Can a potentially infinite list> > > > > > > > > > > of potentially infinite 0/1> > > > > > > > > > > sequences have the property that> > > > > > > > > > >    if s is a potentially infinite 0/1> > > > > > > > > > >    sequence, then s is a line of L>> > > > > <snip>> > > > > > For every s: There is alsways a list that contains the first n bits of> > > > > > s.>> > > > > Is there a single line which contains s> > > > > Yes or no>> > > <snip>>> > > > There is no complete s.>> > > Then the answer is no>> > Indeed, since there is no single line, l,> > such that every initial segment of s is contained> > in l, we do not even have to talk about complete s.->> In fact we can say that in a suitable list "every" initial segment of> s is contained in some line, since there is no s(n) = (s1, s2, ...,> sn) missing. But there is no sensible way of saying "all" initial> segment.We can say  "every line has the property that itdoes not contain every initial segment of segment of s"There is no need to use the concept "all".
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