Date: Feb 5, 2013 9:23 AM
Author: Milo Gardner
Subject: Re: Archimedes square root of 3
typos again ... fixed ...

E.J. Dijkerhuis "Archimedes" (1987) page 435 discussed

(27^1/2)/3 in terms of a continuing fraction series

cited 3^1/2, 26/15, 265/153, 1351/780

followed by

"... what(would) a more satisfactory solution of the question could possibly look like like?"

Archimedes' method solved (27^1/2)/3 in two steps

1. [(5 + 1/5)^]2/3 = (27 + 1/25)/3

2. [1/25) x 5/52)]/3 = (1/260)/3

such that

(5 + 1/5 + 1/25 - 1/260)/3 = 1351/780

cited in ...

http://planetmath.org/encyclopedia/EgyptianAndGreekSquareRoot.html