Date: Feb 7, 2013 3:02 AM
Author: mueckenh@rz.fh-augsburg.de
Subject: Matheology § 222
On 7 Feb., 08:39, Virgil <vir...@ligriv.com> wrote:

> In article

> <bbdf841d-effe-48c8-b938-0825f9e82...@fv9g2000vbb.googlegroups.com>,

>

> WM <mueck...@rz.fh-augsburg.de> wrote:

> > Matheology § 222 Back to the roots

>

> > Consider a Cantor-list with entries a_n and anti-diagonal d:

>

> > For every n: (a_n1, a_n2, ..., a_nn) =/= (d_1, d_2, ..., d_n).

> > For every n: (a_n1, a_n2, ..., a_nn) is terminating.

> > For every n: (d_1, d_2, ..., d_n) is terminating.

>

> Even if there is last a_n and a last a_nn, n, the d_m's can still go

> on without end..

>

>

>

> > For all n: (a_n1, a_n2, ..., a_nn) =/= (d_1, d_2, ..., d_n).

> > For all n: (a_n1, a_n2, ..., a_nn) is terminating.

> > For all n: (d_1, d_2, ..., d_n) is *not* terminating.

>

> While (d_1, d_2, ..., d_n) may be terminating,

> d_1, d_2, ..., d_n, ... need *not* ever terminate.

The diagonal argument includes merely all (d_1, d_2, ..., d_n).

Regards, WM