```Date: Feb 11, 2013 1:23 PM
Author: Koobee Wublee
Subject: Re: Charged mass exact solutions to Einstein's field equations

On Feb 10, 5:36 pm, David Waite wrote:> Implications of new exact solutions of Einstein's field> equations I've found and a particular coordinate expression> of the charged black hole solution are discussed at the video link> https://www.youtube.com/watch?v=M1WcSCsCFckThe Reissner-Nordstrom metric has the following form:**  ds^2 = c^2 T (1 ? K / r + L / r^2) dt^2         - dr^2 / (1 ? K / r + L / r^2) ? r^2 dO^2Where**  T, K, L = Constants**  dO^2 = cos^2(Latitude) dLongitude^2 + dLatitude^2Well, it does not satisfy the vacuum field equations unless (L = 0)which becomes the Schwarzschild metric.  Thus, the Reissner-Nordstrommetric is wrong.  The closest metric to Reissner-Nordstrom metric isthe one below.**  ds^2 = c^2 T (1 ? K / R) dt^2         - dr^2 (dR/dr)^2 / (1 ? K / R) ? R^2 dO^2Where**  R = r / (1 ? L/K / r)Torturously listening to these monotonous rambling at 1:30 into theboring presentation, you showed the following metric as atransformation for the good old Schwarzschild metric.**  ds^2 = c^2 dt^2 / (1 + K / r)^2         ? (1 + K / r)^2 dr^2 ? (1 + K / r)^2 r^2 dO^2The above metric is wrong in which it does not satisfy the null Riccitensor.  The solution you are looking for is:**  ds^2 = c^2 T (1 ? K / R) dt^2         - dr^2 (dR/dr)^2 / (1 ? K / R) ? R^2 dO^2Or**  ds^2 = c^2 dt^2 / (1 + K / r)         ? (1 + K /r) dr^2 ? (1 + K / r)^2 r^2 dO^2Where**  R = r + KThe metric above and the Schwarzschild metric are both valid solutionsto the null Ricci tensor.  The Schwarzschild metric manifests blackholes in the infinite future, but the metric above does not.  <shrug>The Reisnner-Nordstrom metric has the electric static force obeyingthe inverse cubed law instead of inverse squared law.  The self-styledphysicists have a better chance of fudged Coulomb?s law with thefollowing modification to the Schwarzschild metric.**  ds^2 = c^2 (1 ? K / r + L / r) dt^2         - dr^2 / (1 ? K / r + L / r) ? r^2 dO^2Where**  L = Constant that would make up Coulomb?s lawWaite is becoming an embarrassment to the Einstein Dingleberries, andGR is becoming a bigger embarrassment to self-styled physicists.<shrug>
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