Date: Feb 17, 2013 11:54 AM
Author: mueckenh@rz.fh-augsburg.de
Subject: Re: Matheology § 222 Back to the roots

On 16 Feb., 15:32, William Hughes <wpihug...@gmail.com> wrote:
> On Feb 16, 1:04 pm, WM <mueck...@rz.fh-augsburg.de> wrote:
>

> > On 15 Feb., 23:58, William Hughes <wpihug...@gmail.com> wrote:
> > > So WMs statements are
>
> > > there is a line l such that d and l
> > > are coFIS

>
> > Of course, for every n there is a line 1, 2, 3, ..., n that is coFIS
> > to the diagonal 1, 2, 3, ..., n.

>
> Nope.  a line  is either coFIS to d or it is not.


Yes, of course.
And this holds for every n that you have.
>
> It makes sense to say
>
>      For every n there is a line, l(n) such that
>      the nth FIS of d.
>      But this does not make l(n) coFIS to d.


Again you confuse actual with potential infity.
Again: d is nothing more than every FIS d_1, ,,,,, d_n

So for every n there is a line that is coFIS.
And more is simply not available in potential infinity.
>
>  And there is not more than every n.
>

> > > there is no line l such that d and l
> > > are coFIS

> > That would only be true if there was an n larger than every n
>
> ??  The statement is yours.  Are you now withdrawing it.


No the statement concerns anti-diagonals and does not concern the
notion of coFIS.

You are continuously confusing d (more than every FIS) with every FIS
d_1, ..., d_n.
Please learn: In potential infinity (and in correct and not self-
contradictory math) there is nothing more of d than every d_1, ...,
d_n.

And exactly this is in the lines for every n.

Regards, WM