Date: Feb 17, 2013 11:54 AM
Author: mueckenh@rz.fh-augsburg.de
Subject: Re: Matheology § 222 Back to the roots
On 16 Feb., 15:32, William Hughes <wpihug...@gmail.com> wrote:

> On Feb 16, 1:04 pm, WM <mueck...@rz.fh-augsburg.de> wrote:

>

> > On 15 Feb., 23:58, William Hughes <wpihug...@gmail.com> wrote:

> > > So WMs statements are

>

> > > there is a line l such that d and l

> > > are coFIS

>

> > Of course, for every n there is a line 1, 2, 3, ..., n that is coFIS

> > to the diagonal 1, 2, 3, ..., n.

>

> Nope. a line is either coFIS to d or it is not.

Yes, of course.

And this holds for every n that you have.

>

> It makes sense to say

>

> For every n there is a line, l(n) such that

> the nth FIS of d.

> But this does not make l(n) coFIS to d.

Again you confuse actual with potential infity.

Again: d is nothing more than every FIS d_1, ,,,,, d_n

So for every n there is a line that is coFIS.

And more is simply not available in potential infinity.

>

> And there is not more than every n.

>

> > > there is no line l such that d and l

> > > are coFIS

> > That would only be true if there was an n larger than every n

>

> ?? The statement is yours. Are you now withdrawing it.

No the statement concerns anti-diagonals and does not concern the

notion of coFIS.

You are continuously confusing d (more than every FIS) with every FIS

d_1, ..., d_n.

Please learn: In potential infinity (and in correct and not self-

contradictory math) there is nothing more of d than every d_1, ...,

d_n.

And exactly this is in the lines for every n.

Regards, WM