```Date: Feb 17, 2013 11:54 AM
Author: mueckenh@rz.fh-augsburg.de
Subject: Re: Matheology § 222 Back to the roots

On 16 Feb., 15:32, William Hughes <wpihug...@gmail.com> wrote:> On Feb 16, 1:04 pm, WM <mueck...@rz.fh-augsburg.de> wrote:>> > On 15 Feb., 23:58, William Hughes <wpihug...@gmail.com> wrote:> > > So WMs statements are>> > > there is a line l such that d and l> > > are coFIS>> > Of course, for every n there is a line 1, 2, 3, ..., n that is coFIS> > to the diagonal 1, 2, 3, ..., n.>> Nope.  a line  is either coFIS to d or it is not.Yes, of course.And this holds for every n that you have.>> It makes sense to say>>      For every n there is a line, l(n) such that>      the nth FIS of d.>      But this does not make l(n) coFIS to d.Again you confuse actual with potential infity.Again: d is nothing more than every FIS d_1, ,,,,, d_nSo for every n there is a line that is coFIS.And more is simply not available in potential infinity.>>  And there is not more than every n.>> > > there is no line l such that d and l> > > are coFIS> > That would only be true if there was an n larger than every n>> ??  The statement is yours.  Are you now withdrawing it.No the statement concerns anti-diagonals and does not concern thenotion of coFIS.You are continuously confusing d (more than every FIS) with every FISd_1, ..., d_n.Please learn: In potential infinity (and in correct and not self-contradictory math) there is nothing more of d than every d_1, ...,d_n.And exactly this is in the lines for every n.Regards, WM
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