Date: Feb 17, 2013 4:24 PM
Subject: Re: Matheology � 222 Back to the roots
WM <email@example.com> wrote:
> On 16 Feb., 16:26, William Hughes <wpihug...@gmail.com> wrote:
> > > the nth FIS of l(n) is the nth FIS of d .
> > > But this does not make l(n) coFIS to d.
> > > > > And there is not more than every n.
> > > > > there is no line l such that d and l
> > > > > are coFIS
> > > > That would only be true if there was an n larger than every n
> > > ?? The statement is yours. Are you now withdrawing it.-
> The statement is just to the point.
> You said: there is no line l such that d and l are coFIS
> I said: That (your statement) would only be true if there was an n
> larger than every n (but there isn't).
There is, however, a natural larger than any previously given natural.
> There is only every d_n and for every d_n there is a line containing
> it. Otherwise it could not be a d_n.
And for EVERY line, a d_n NOT contained in it!
In fact, more d_n's not contained in it than are contained in it.
> You are, again, arguing with finished infinity, d having more than
> every d_n.
If you object to that then you must be arguing that d does not have
more than at least one of its d_n.
WHich d_n would that be, WM?