Date: Feb 20, 2013 11:44 AM
Author: William Hughes
Subject: Re: Matheology § 222 Back to the roots
On Feb 20, 5:29 pm, WM <mueck...@rz.fh-augsburg.de> wrote:

> On 20 Feb., 13:31, William Hughes <wpihug...@gmail.com> wrote:

>

> > On Feb 20, 12:37 pm, WM <mueck...@rz.fh-augsburg.de> wrote:

>

> > > On 20 Feb., 11:30, William Hughes <wpihug...@gmail.com> wrote:

> > <snip>

> > > > A statement you can make is that there

> > > > is no line of the list with the property

> > > > that it is coFIS to d.

> > > > (you do not need every line or every FIS to "actually

> > > > exist" to make this statement)

>

> > > You need all FISs of d to make this statement.

>

> > No, for each line of L you only need some

> > of the FISs. For every line you need every

> > not all.

>

> Then you have a statement for finitely many lines and none for

> infinitely many lines.

>

>

>

>

>

>

>

>

>

>

>

> > <snip>

>

> > > > Let z be a potentially infinite sequence such that

> > > > for some natural number m, the mth FIS of

> > > > z contains a zero.

>

> > > > Are z and x coFIS?

>

> > > No.

>

> > Is the following statement true

>

> > For every natural number n we have

>

> > the (n+1)st FIS of the nth line

> > of L contains a 0.

>

> Of course.

Is the statement

For every natural number n we have

the nth line of L and x

are not coFIS

true?