Date: Feb 23, 2013 4:36 PM Author: plutonium.archimedes@gmail.com Subject: rough-deriving rest-masses of 0.5, 938, 105 MeV #1253 New Physics<br> #1373 ATOM TOTALITY 5th ed Rough-deriving rest-masses of 0.5, 938, and 105 MeV. Of course those

are electron, proton and muon respectively.

What follows is some rough play calculations to see

if I can come at all close to the numbers. And keep in mind that the

calculations are counting of the ridges and troughs of standing waves

that have looped back around creating a standing wave. A photon has no

rest-mass because the wave has no circles or loops in it but is more

or less a straight line wave. A particle that has rest mass has part

of its wave circling around into forming a circle or surface area or

volume.

I am working with just plain spheres and circles but I need to work

with ellipsoids for more precision.

Now I need all three formulas of circumference, surface area and

volume:

(a) C = pi(2r)

(b) S.A. = 4pi(r^2)

(c) V = 4/3(pi)(r^3)

Now I have not found out the characteristics of the wavelength of the

hydrogen atom electron or proton so I am going to assume with a

hypothetical number,

the number 300 as a unit of measure, purely hypothetical to see if 300

gives me 0.5, 938, and 105 MeV.

For the electron we have 300 x 300 = 90,000. And if the radius is

90,000 then pi(2r) is 540,000 and for this hypothetical 540,000 is

close enough to 0.5 MeV

For the muon we have (300)^3 = 27,000,000. So if the radius is 300

then the volume is 4/3(pi)(r^3) so that 4 x 27,000,000 is 108,000,000

which is close enough to 105 MeV for the muon.

Now for the proton we have surface area but the inverse of the

electron so we have (90,000)^2

= 8,100,000,000 divided by 6 from 2pi of circumference since inverse

we have 1,350,000,000

which is not a good estimate of the proton rest-mass

of 938,000,000 eV.

Now if I was working with ellipsoids for the proton I believe I could

easily get 938,000,000 rather than get 1,350,000,000 with spheres. Now

I do recall the physics literature has the tear drop shape for the

nucleus of radioactive elements. The tear drop shape is an example of

ellipsoids. Now I have to investigate whether the tear drop shape has

some exacting numbers or whether it is just a qualitative description

with no quantitative backing.

The reader must keep in mind that leptons are hyperbolic geometry and

the rest mass is the counting up of ridges and troughs of the standing

wave, whereas the baryons of protons and neutrons are elliptic

geometry and the counting up of ridges and troughs of standing waves.

--

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