Date: Feb 23, 2013 7:25 PM
Author: Virgil
Subject: Re: Matheology � 222 Back to the roots

In article 
<2ad61b7b-0c53-443b-a941-80f8037cfdbd@k8g2000yqb.googlegroups.com>,
WM <mueckenh@rz.fh-augsburg.de> wrote:

> On 23 Feb., 22:48, Nam Nguyen <namducngu...@shaw.ca> wrote:
> > On 23/02/2013 2:38 PM, Virgil wrote:
> >

> > > In article
> > > <f3b2ce4b-c9ec-447f-92b4-47a07a2e2...@5g2000yqz.googlegroups.com>,
> > >   WM <mueck...@rz.fh-augsburg.de> wrote:

> >
> > > In mathematics [...] proofs of existence do
> > > not always require that one find an example of the thing claimed to
> > > exist.

> >
> > So, how would one prove the existence of the infinite set of
> > counter examples of Goldbach Conjecture, given that it does not
> > "not [...] require that one find an example" of such existences?

>
> It there was a logical necessity of a counter example, this necessity
> was the proof. However, I don't see a necessity in this case. So I
> have no proof.
>
> But I see a logical necessity, that the sequence of all last digits of
> the terms of a sequence like the following
>
> 1
> 1, 2
> 1, 2, 3
> ...
>
> does neither contain more digits neither less digits than there are
> terms of the sequence.
>
> Regards, WM


The sequence of last digits can contain no more than ten different
digits which is less than the number of terms when there are more than
ten terms.
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