```Date: Feb 24, 2013 5:56 AM
Author: Milos Milenkovic
Subject: Re: Automating an iterative procedure

Dear dpb,yes, intermediate values of B0 and B1 have to be stored, I have to see when they converge. Any help would be greatly appreciated!Best,M dpb <none@non.net> wrote in message <kgbdd4\$isu\$1@speranza.aioe.org>...> On 2/23/2013 3:01 PM, Milos Milenkovic wrote:> > ...[top posting repaired--please don't:  hard conversation follow makes]...> > > dpb <none@non.net> wrote in message <kgb86j\$446\$1@speranza.aioe.org>...> >> On 2/23/2013 2:04 PM, Milos Milenkovic wrote:> >> ...> >> > K1=[-0.2582 -18.596 0 -0.2582;> >> > -34.737 -1300.188 0 -34.737;> >> ...> >> > for i=1:100> >> > B1(1)=[0.01 0.02 0.07 0.03;> >> > 0.02 0.05 0.06 0.02;> >> > 0.07 0.09 0.01 0.03;> >> > 0.01 0.03 0.02 0.04];> >>> >> ...> >>> >> No, but why would you want to duplicate a constant array anyway?> >> Sometimes for matrix operations there's a need/desire to do so, but> >> generally a temporary via repmat() or some other technique would be> >> more reasonable than just holding multiple copies of the same array.> >>> >> B1(1) refers to a single array location whereas the rhs is an array.> >> "Can't put 5-lbs of 'taters in a 1-lb tote" to use the E TN vernacular.> >>> >> Only a cell array element can hold another array.> >>> > ...> > >> B1(1) and B0(1) are given matrices in iteration 1, then for the next 99> >> iterations I want to calculate updates of these matrices.> > Oh.> > Move the initiation outside the loop then store new values into the > desired location(s) in the array inside the iterative portion (the loop > iow).  To do that you don't need to subscript B1 at all other than to > address individual elements therein if required.  But, if you can > vectorize the computation of B1 then there's no need for the indexing.> > Are you needing to save all iterations to the bitter end?> > --
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