Date: Feb 25, 2013 2:19 AM
Author: David Park
Subject: Re: A nonconventional ListContourPlot

ContourPlot[Sin[x + y^2], {x, -2, 2}, {y, -1, 1},
ColorFunction -> ColorData["DarkRainbow"]]


Rather, why do you want to sample at your strange set of x,y values? Is the
z expression just a stand-in for actual measure values? You might try
Interpolation with InterpolatingOrder -> 1, but the results in this case do
not seem promising.

David Park

From: Luiz Melo []

Good day,

x[a_,b_] = a*b;
y[a_,b_] = Cos[a^2 + b];
z[a_,b_] = Sin[a + b^2];

data = Table[{x[i,j], y[i,j], z[i,j]}, {j, -1, 1, 0.1}, {i, -2, 2, 0.1}];

For the table above, is it possible to see a ListContourPlot of the z
component as a function of x and y (the values of x and y on the horizontal
and vertical axes, respectively)?

Thank you in advance
Luiz Melo