Date: Feb 25, 2013 2:19 AM
Author: David Park
Subject: Re: A nonconventional ListContourPlot
ContourPlot[Sin[x + y^2], {x, -2, 2}, {y, -1, 1},

ColorFunction -> ColorData["DarkRainbow"]]

??

Rather, why do you want to sample at your strange set of x,y values? Is the

z expression just a stand-in for actual measure values? You might try

Interpolation with InterpolatingOrder -> 1, but the results in this case do

not seem promising.

David Park

djmpark@comcast.net

http://home.comcast.net/~djmpark/index.html

From: Luiz Melo [mailto:lmelo@ufsj.edu.br]

Good day,

x[a_,b_] = a*b;

y[a_,b_] = Cos[a^2 + b];

z[a_,b_] = Sin[a + b^2];

data = Table[{x[i,j], y[i,j], z[i,j]}, {j, -1, 1, 0.1}, {i, -2, 2, 0.1}];

For the table above, is it possible to see a ListContourPlot of the z

component as a function of x and y (the values of x and y on the horizontal

and vertical axes, respectively)?

Thank you in advance

Luiz Melo