Date: Feb 27, 2013 5:22 AM
Author: Tony Kittler
Subject: Re: Alternative solution for NAN
"Torsten" wrote in message <kgklbh$6ph$1@newscl01ah.mathworks.com>...

> "Carl S." wrote in message <kgki2g$rie$1@newscl01ah.mathworks.com>...

> > The following code gives NAN (Not a Number) values

> > [U,D]=eig(N);

> >

> > To solve this problem, I wrote that

> > while(det(N) == 0)

> > N=(1e-10.*randi(1,size(N)))*eye(size(N));

> > end

> >

> > But, the loop does not stop

>

> Your matrix N within the loop always has determinant (1e-10)^(size(N))

> which may become very small if N is large.

>

> :( Are there any alternative solution instead of this loop to solve the NAN problem ?

>

> Depends on the original matrix N.

>

> Best wishes

> Torsten.

Dear Torsten,

The matrix N has standard deviation values of grayscale images. So, it changes for each image. How to solve the NAN problem in this case ?