Date: Mar 7, 2013 3:56 PM
Subject: Re: Matheology � 222 Back to the roots
WM <firstname.lastname@example.org> wrote:
> On 7 Mrz., 11:35, William Hughes <wpihug...@gmail.com> wrote:
> > On Mar 7, 11:12 am, WM <mueck...@rz.fh-augsburg.de> wrote:
> > > On 6 Mrz., 23:48, William Hughes <wpihug...@gmail.com> wrote:
> > > > On Mar 6, 7:44 pm, WM <mueck...@rz.fh-augsburg.de> wrote:
> > > > > On 6 Mrz., 13:18, William Hughes <wpihug...@gmail.com> wrote:
> > > > <snip>
> > > > > > A subset K of the lines of L
> > > > > > contains every FIS of d iff
> > > > > > K has no findable last line.
> > > > > No
> > > > Let G be a subset of the lines of L
> > > > with a findable last line. Call
> > > > this line g.
> > Note
> > There does not exist
> > (in the sense of not findable)
> > a natural number m such that
> > the mth line of L is coFIS with
> > d
> Note, there does not exist d other than as every FIS.
There does outside of WMytheology. In real mathematics, d is merely the
union of all lines, which is not itself one of those lines.
>These FISs are
> the same as the lines. Every findable thing in one set has a
> corresponding finadable thing in the other. There is no difference
One set, the set of lines, is the set of FISs of the other, d
Every line is subset of d, but no line is a member of d.
WM has a long history of being unable to distinguish between the members
of and the subsets of a given set, and that difference appears here to
be confounding him again.
> Regards, WM
And where is WM's proof that some mapping from the set of all binary
sequences to the set of all paths of a CIBT is a linear mapping?
WM several times claimed it but cannot seem to prove it.