Date: Mar 8, 2013 2:28 PM
Author: mueckenh@rz.fh-augsburg.de
Subject: Re: Matheology § 222 Back to the roots
On 8 Mrz., 17:15, William Hughes <wpihug...@gmail.com> wrote:

> On Mar 8, 4:55 pm, WM <mueck...@rz.fh-augsburg.de> wrote:

>

> > On 8 Mrz., 15:45, William Hughes <wpihug...@gmail.com> wrote:

>

> > > WM: There does not exist

> > > (in the sense of not findable)

> > > a natural number m such that

> > > the mth line of L is coFIS with

> > > d

>

> > > So let's talk about d the way you

> > > talk about d.

>

> You find it reasonable to say

>

> a line of L is not coFIS with d

L = d

Every line L_k of L is identical with FIS d_1, ..., d_k of d.

d is nothing but it sFIS

>

> The question is

>

> Do you agree with the statement

>

> g is not coFIS with d.

Let us remember:

Two potentially infinite sequences x and y are said to be coFIS iff

for every natural number n, the nth FIS of x is equal to the nth FIS

of y.

This is obviously the case for that line L_max which is identical with

the maximal FIS of d:

1, 2, 3, ..., max = 1, 2, 3, ..., max

On the the left-hand side you see the line L_max or g, on the right-

hand side you see d, i.e., everything that in potential infinity can

be assumed to exist of lines and d.

Regards, WM