Date: Mar 10, 2013 5:46 AM
Subject: Re: Matheology § 222 Back to the roots
On 10 Mrz., 01:37, Virgil <vir...@ligriv.com> wrote:
> And where is WM's proof that some mapping from the set of all binary
> sequences to the set of all paths of a CIBT is a linear mapping?
> WM several times claimed it but cannot seem to prove it.
You will not understand it. Or you will deny the definition. Or you
will simply make trouble as your well-known favourite occupation.
Therefore I said EOD with respect to this topic.
If ax + by exists, then f(ax + by) = af(x) + bf(y).
If ax + by does not exists, then f(ax + by) and af(x) + bf(y) do not
This is my definition of isomorphism.
Accept it or not, understand it or not.
E O D ! ! !