```Date: Mar 10, 2013 4:35 PM
Author: Virgil
Subject: Re: Matheology � 222 Back to the roots

In article <e8e9544e-c94f-47fc-81e7-673ad702706e@r8g2000vbj.googlegroups.com>, WM <mueckenh@rz.fh-augsburg.de> wrote:> On 10 Mrz., 01:37, Virgil <vir...@ligriv.com> wrote:> > > And where is WM's proof that some mapping from the set of all binary> > sequences to the set of all paths of a CIBT is a linear mapping?> > WM several times claimed it but cannot seem to prove it.> > You will not understand it. Or you will deny the definition. Or you> will simply make trouble as your well-known favourite occupation.> Therefore I said EOD with respect to this topic.> > If ax + by exists, then f(ax + by) = af(x) + bf(y).> If ax + by does not exists, then f(ax + by) and af(x) + bf(y) do not> exist.> This is my definition of isomorphism.> Accept it or not, understand it or not.It may be WM's definition of "isomorphism", but how is that relevant without showing that such a mapping exists between the relevant sets and that it is an isomorphism? Which he has not done!WM has claimed that a mapping from the set of all infinite binary sequences to the set of paths of a CIBT is a linear mapping.In order to show that such a mapping is a linear mapping, WM must first show that the set of all binary sequences is a vector space and that the set of paths of a CIBT is also a vector space, which he has not done and apparently cannot do, and thene show that his mapping satisfiesf(ax + by) = af(x) + bf(y), where a and b are arbitrary members of the field of scalars and x and y are binary sequences and f(x) and f(y) are paths in a CIBT.By the way, WM, what are ax and by and ax+by when x and y are binary sequences? If a = 1/3 and x is binary sequence, what is ax ?and if f(x) is a path in a CIBT, what is af(x)?Until these and a few other issues are settled, WM will still have failed to justify his claim of a LINEAR mapping from the set (but not yet proved to be vector space) of binary sequences to the set (but not yet proved to be vector space) of paths ln a CIBT.--
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