Date: Mar 11, 2013 3:41 PM
Author: Virgil
Subject: Re: Matheology � 222 Back to the roots
In article

<23120302-a8cc-40ba-879e-a763061c8cf5@hl5g2000vbb.googlegroups.com>,

WM <mueckenh@rz.fh-augsburg.de> wrote:

> On 10 Mrz., 20:52, William Hughes <wpihug...@gmail.com> wrote:

>

> > Let l be a line of L

> >

> > Do you agree with the statement

> >

> > For every n, the nth FIS of d is

> > contained in l iff

> > l is coFIS to (d)

>

> or, more precisely: to the sequence 1, 2, 3, ..., max defined by (d).

> Yes, that is right.

>

> Note: since max is not findable, we can state that for every findable

> part of d there is a line identical with that part. For the unfindable

> 1, 2, 3, ..., max defined by (d) there is the unfindable last line 1,

> 2, 3, ..., max defined by (l).

>

Nonsense! But if there are countably many unfindable naturals, and if

there are any there must be countably many of them, there can be

unfindable reals, and can be uncountably many of them, ever since Cantor.

WM has claimed that a mapping from the set of all infinite binary

sequences to the set of paths of a CIBT is a linear mapping.

In order to show that such a mapping is a linear mapping, WM must first

show that the set of all binary sequences is a vector space and that the

set of paths of a CIBT is also a vector space, which he has not done and

apparently cannot do, and then show that his mapping satisfies

f(ax + by) = af(x) + bf(y), where a and b are arbitrary members of the

field of scalars and x and y are binary sequences and f(x) and f(y) are

paths in a CIBT.

By the way, WM, what are ax and by and ax+by when x and y are binary

sequences?

If a = 1/3 and x is binary sequence, what is ax ?

and if f(x) is a path in a CIBT, what is af(x)?

Until these and a few other issues are settled, WM will still have

failed to justify his claim of a LINEAR mapping from the set (but not

yet proved to be vector space) of binary sequences to the set (but not

yet proved to be vector space) of paths ln a CIBT.

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