Date: Mar 13, 2013 5:52 AM
Author: mueckenh@rz.fh-augsburg.de
Subject: Re: Matheology § 222 Back to the roots
On 12 Mrz., 23:20, Virgil <vir...@ligriv.com> wrote:

>

> WM has frequently claimed that a mapping from the set of all infinite

> binary sequences to the set of paths of a CIBT is a linear mapping.

> In order to show that such a mapping is a linear mapping, WM must first

> show that the set of all binary sequences is a vector space and that the

> set of paths of a CIBT is also a vector space, which he has not done and

> apparently cannot do,

The field of real numbers (|R, +, *) should satisfy your wishes.

Written in the form of a tree with the decimal point common to all

paths that stretch from oo to -oo you get the same space as a decimal

tree. And if you translate that into binaries, you have the desired

fields.

You can here without any limits add and subtract and multiply and

divide.

Here is a sketch of the resulting Binary Tree extended to a complete

space:

...

0 1 0 1

\/ \/

0 1

\ /

.

/ \

0 1

/\ /\

0 1 0 1

...

Are you really too stupid to create such a simple structure by

yourself?

Or do you only want to distract the reader from the well known

contradiction?

Regards, WM