Date: Mar 13, 2013 5:52 AM
Author: mueckenh@rz.fh-augsburg.de
Subject: Re: Matheology § 222 Back to the roots

On 12 Mrz., 23:20, Virgil <vir...@ligriv.com> wrote:

>
> WM has frequently claimed that a mapping from the set of all infinite
> binary sequences to the set of paths of a CIBT is a linear mapping.
> In order to show that such a mapping is a linear mapping, WM must first
> show that the set of all binary sequences is a vector space and that the
> set of paths of a CIBT is also a vector space, which he has not done and
> apparently cannot do,


The field of real numbers (|R, +, *) should satisfy your wishes.
Written in the form of a tree with the decimal point common to all
paths that stretch from oo to -oo you get the same space as a decimal
tree. And if you translate that into binaries, you have the desired
fields.

You can here without any limits add and subtract and multiply and
divide.

Here is a sketch of the resulting Binary Tree extended to a complete
space:

...
0 1 0 1
\/ \/
0 1
\ /
.
/ \
0 1
/\ /\
0 1 0 1
...

Are you really too stupid to create such a simple structure by
yourself?

Or do you only want to distract the reader from the well known
contradiction?

Regards, WM