Date: Mar 20, 2013 4:21 PM
Author: William Hughes
Subject: Re: Matheology § 224

On Mar 20, 9:17 pm, WM <mueck...@rz.fh-augsburg.de> wrote:
> On 20 Mrz., 21:01, William Hughes <wpihug...@gmail.com> wrote:
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> > On Mar 20, 8:57 pm, WM <mueck...@rz.fh-augsburg.de> wrote:
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> > > On 20 Mrz., 20:40, William Hughes <wpihug...@gmail.com> wrote:
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> > > > On Mar 20, 4:24 pm, WM <mueck...@rz.fh-augsburg.de> wrote:
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> > > > > I show that every line, that is not the last line, is not needed.
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> > > > Nope.  You show that it is not necessary for its contents.
> > > > This is not the same as not needed.

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> > > Agreed:
> > > I show that every line, that is not the last line, is not needed to
> > > remain in the list in order to have its contents in the list.
> > > Agreed?

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> > Nope.  It may be needed for something else whose contents are
> > needed (in this case the tail of the list) to exist.

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> Please name a line that is needed for the tail of the list to exist.
> (You do agree that every set of lines has a first element?)
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We need an infinite number of lines.
Choose lines 3,4,6,7,8...
Then line 3, being one of the needed set chosen is needed.
Note, that we do not have to choose line 3, so line
3 is not necessary.

Compare to choosing a basis for |R^2. Two vectors
are needed. However, there is no necessary vector.