Date: Mar 26, 2013 5:15 PM
Author: Virgil
Subject: Re: Matheology � 224
In article

<cfe2243a-02d8-430f-89cc-3763a24bb51f@r6g2000yqh.googlegroups.com>,

WM <mueckenh@rz.fh-augsburg.de> wrote:

> On 26 Mrz., 21:00, Virgil <vir...@ligriv.com> wrote:

> > In article

> > <6eabd00e-1678-4e4e-8281-22b180dbc...@m12g2000yqp.googlegroups.com>,

> >

> >

> >

> >

> >

> > WM <mueck...@rz.fh-augsburg.de> wrote:

> > > On 26 Mrz., 00:18, Virgil <vir...@ligriv.com> wrote:

> > > > In article

> > > > <ad404888-6726-4aa3-b421-fcc887b93...@7g2000yqy.googlegroups.com>,

> >

> > > > WM <mueck...@rz.fh-augsburg.de> wrote:

> > > > > So the set of all rational numbers always contains all irrational

> > > > > numbers? Or only some? Or is that a speciality of the Binary Tree?

> >

> > > > It is a speciality of a complete binary tree.

> >

> > > > It is something that would be fairly obvious to any competent

> > > > mathematician, which is, no doubt, why it is not obvious to WM.

> > > > --

> >

> > > I let this stand as it is.

> >

> > I should have said a Complete INFINITE Binary Tree.

>

> But I have asked for the Binary Tree that only contains the rational

> paths.

If it contains ALL binary rational paths, it cannot help containing

others as well.

> >

> > There is no Complete INFINITE Binary Tree which can represent only

> > all binary rationals in the interval [0,1]

>

> Of course. But my question is not so easy to answer.

>

> Regards, WM

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