```Date: Mar 30, 2013 2:03 PM
Author: Virgil
Subject: Re: Matheology � 224

In article <050b4a95-d2b0-433b-98b6-d63c34635cb7@m9g2000vbc.googlegroups.com>, WM <mueckenh@rz.fh-augsburg.de> wrote:> On 29 Mrz., 19:40, Virgil <vir...@ligriv.com> wrote:> > In article> > <ce3c22f2-9116-4621-b3b4-e722fe51a...@a14g2000vbm.googlegroups.com>,> >> >  WM <mueck...@rz.fh-augsburg.de> wrote:> > > On 26 Mrz., 22:47, Virgil <vir...@ligriv.com> wrote:> >> > > > But a tree that contains paths for all binary rationals will contain a> > > > path for all limits of a sequences of binary rationals.> >> > > Does a sequence always contain its limit?> >> > Depends on the sequence, of course. but a sequence of paths in a> > Complete Infinite Binary Tree in which the nth path must share at least> > n nodes with each of its successors will always converge, though not> > neccessarily to a binary rational.> > A sequence of numbers may converge, but not necessarily to a limit> that is a term of the sequence.Precisely my point!> A sequence of paths may converge, but not necessarily to a limit that> is a term of the sequence.So WM acknowledges that A sequence of binary rational paths can converge to a path that is not a binary rational.> > In mathematics more precision is required.Certainly more than WM is capable of producing,.> > > >> >> >> > In a COMPLETE INFINITE BINARY TREE, all paths are actually infinite> > --> > This is again a simple statement of countermathematical  belief It is matter of simple definition. The definition of a COMPLETE Infinite Binary Tree requires that no path in such a tree can terminate.At least it does so everywhere outside of Wolkenmuekenheim,--
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