Date: Apr 12, 2013 2:34 AM
Author: William Hughes
Subject: Re: Matheology § 238
On Apr 12, 7:40 am, WM <mueck...@rz.fh-augsburg.de> wrote:

> On 11 Apr., 23:52, William Hughes <wpihug...@gmail.com> wrote:

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> > On Apr 11, 9:51 pm, WM <mueck...@rz.fh-augsburg.de> wrote:

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> > > On 11 Apr., 20:52, William Hughes <wpihug...@gmail.com> wrote:

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> > > > On Apr 11, 8:17 pm, WM <mueck...@rz.fh-augsburg.de> wrote:

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> > > > > On 11 Apr., 19:19, William Hughes <wpihug...@gmail.com> wrote:

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> > > > > > > So you agree that B implies A.

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> > > > > > yep, but A does not imply C: P(d_1,d_2,d_3..)

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> > > > > That is your interpretation.

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> > > > One you agree with,

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> > > Not at all!

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> > Yep, you have agreed that saying something is true for

> > every element of a collection does not imply that it

> > is true for the collection.

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> It is true for all elements.

Correct every element has the property that it can be removed.

>No mentioning of collection.

Correct, the collection cannot be removed without changing

the union, and you cannot leave no lines without removing the

collection of lines.

> I am not at

> all interested whether these elements form something like a

> collection. Of course you cannot say that the collection of real

> numbers is a real number. But when all real numbers have been

> removed, the collection has gone too.

Correct. Removing all elements is the same as removing the

collection.

Now let P be (can remove the collection without changing

the union of the remaining lines). We have there is no

contradiction in saying A: for all n, the nth line can be removed

because A does not imply C and only C is a contraction.