```Date: Apr 19, 2013 10:05 AM
Author: Curious
Subject: Re: problem in if else !!!!!!!!!!!!

"KARTIK ARG" <argkarthik@yahoo.com> wrote in message <kkqfgb\$obt\$1@newscl01ah.mathworks.com>...> in this prgm  bin contains 0s and 1s in random.> now i want to print 'after mutation' when bin value contains 0 and 'after mu' when bin value contains 1.So, whats the problem?  Whats your question?> > clc;> clear all;> % >> Inititalizing Population...> m=0.47;s=5;> z=1;> popdec=cell(20,5);> popbin=cell(20,5);> vi(1,1)=0;low=0;> for i=1:20>     for j=1:5>         if j==1>             lim=low+(80-low)*(rand);>             popdec{i,j}=ceil(lim);        % Generating random numbers b/w 1 to 90>             z=j;>         else>             lim=popdec{i,z}+(90-popdec{i,z})*rand;>             popdec{i,j}=ceil(lim);>             z=j;>         end>     end      > end> > for i=1:20>     for j=1:5>         store=popdec{i,j};                  % population in decimal>         popbin{i,j}=dec2bin(store,8);       % population in binary>     end> end> bin=cell2mat(popbin);> for i=1:20>     for j=1:40>         z=mod(j,2);>         if z==1>         v1(1,1)=bin(i,j);>         t=v1(1,1)>         else>             v2(1,1)=bin(i,j);>             t=v2(1,1)>         end>     >   if t==0>             disp('aftr mutation');>             >         else>             disp('aftr mut');>   end>     end> end
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