Date: Apr 25, 2013 1:21 AM Author: David Petry Subject: Re: Ask-an-Analysis problem On Wednesday, April 24, 2013 4:16:42 PM UTC-7, dull...@sprynet.com wrote:

> On Wed, 24 Apr 2013 17:52:09 +0000 (UTC), Herman Rubin

> <hrubin@skew.stat.purdue.edu> wrote:

>> The general solution is

>>f(x)=x^q*h(log_2(x)), where h is any function.

> ??? Since log_2 is 1-1, allowing h to be any function

> here says that f can be any function.

Where h is periodic with period 1.