Date: Apr 25, 2013 1:21 AM
Author: David Petry
Subject: Re: Ask-an-Analysis problem

On Wednesday, April 24, 2013 4:16:42 PM UTC-7, dull...@sprynet.com wrote:
> On Wed, 24 Apr 2013 17:52:09 +0000 (UTC), Herman Rubin
> <hrubin@skew.stat.purdue.edu> wrote:


>> The general solution is
>>f(x)=x^q*h(log_2(x)), where h is any function.


> ??? Since log_2 is 1-1, allowing h to be any function
> here says that f can be any function.


Where h is periodic with period 1.