Date: May 19, 2013 2:20 PM
Author: nepomucenocarlos68@gmail.com
Subject: Floor of the log equation: s = (floor(log10(x))+1)*x - round((10^(floor(log10(x))+1)-10)/9)

Hi guys! I need your help to solve this equation:I need to find 'x' for a given 's'. Both of them are natural numbers (>0).I don't know how to handle the floor term.[octave/matlab format]s = (floor(log10(x))+1)*x - round((10^(floor(log10(x))+1)-10)/9);[or TeX} s = \left( \lfloor\log(x)\rfloor+1 \right)x - \frac{10^{\lfloor\log(x)\rfloor+1}-10}{9}[or image]http://postimg.org/image/r5fd2enll/Exact or approximate values are good.Is there a solution? How do I solve it?Are there any methods to search & find a solution?Regards,Carlos